M
a sh q l a r
Ko‘phadlarni
ko‘paytiring (283–291):
283.
1) (a+2)(a+3); 3) (m+6)(n–1);
2) (z–1)(z+4); 4) (9b+4)(c+5).
284.
1) (c–4)(d–3); 3) (x+y)(x+1);
2) (a–10)(–a–2); 4) (–p–q)(–1–q).
285.
1) (2x+1)(x+4); 3) (3m–2)(2m–1);
2) (2a+3)(5a–4); 4) (5p–3q)(4p–q).
286.
1) (
a+3b)(a–3b); 3)
(
a–2b)(a+2b);
2) (0,3–m)(m+0,3); 4) (0,2a+0,5x) (0,2a–0,5x).
287.
1) (a2+b)(a+b2); 3) (a2+2b)(2a+b2);
2) (5x2–6y2)(6x2–5y2); 4) (x2+2x+1)(x+3).
288.
1) (2a–b)(4a2+2ab+b2); 3) (5x+3y)(25x2–15xy+9y2);
2) (3a–b)(9a2+2ab+b2); 4) (3a+2b)(9a2–6ab+4b2).
289.
1) (5c–4y)(–8c–2x+6y); 3)
(4x–3y+2z)(3x–3y);
2) (4b–c)(–5b+3c–4y); 4) (3a–3b+4c)(3a–5b).
290.
1) (0,2x+0,2y–z)(x–y); 3)
(m–n+
p)(60m+12);
2) (0,3x–0,3y+z)(x+y); 4) (0,1a2–0,3a+1)(3a2–10).
291.
1) (a–b)(a+b)(a–3b); 3) (x+3)(2x–1)(3x+2);
2) (a+b)(a–b)(a+3b); 4) (x–2)(3x+1)(4x–3).
292.
1) (5x–1)(x+3)–(x–2)(5x–4) ifodaning
qiymati x=2
bo‘lganda 49 ga tengligini ko‘rsating;
2) (a+3)(9a–8)–(2+a)(9a–1)
ifodaning qiymati a= –3,5 bo‘lganda
–29 ga tengligini ko‘rsating.
293.
Ifodaning qiymatini hisoblang:
1)
(n+)(n2+n+
), bunda
n= –2;
2)
(n–)(n2+n+
), bunda
n= –
294.
1) ABCD to‘g‘ri to‘rtburchakning
(11-rasm) yuzi (a+b)(c+d)=ac+bc+ad+bd ekanligini ko‘rsating.
2) ABFE to‘g‘ri to‘rtburchakning (12-rasm) yuzi (a+b)(c–d)=ac+bc–ad–bd ekanligini ko‘rsating.
