M a sh q l a r

   

   Quyidagi mashqlarda ikkihadning kvadratini ko‘phad shaklida tasvirlang (365–372):

         

365.       1) (c+d)2;                  3) (2+x)2;              5) (y+3)2;

          2) (x–y)2;                            4) (x+1)2;              6) (7+m)2.

 

366.       1) (m–2)2;                 3) (7–m)2;             5) (a+)2;

          2) (x–3)2;                  4) (y–6)2;              6) (b+)2.

 

367.       1) (q+2p)2;         2) (3x+2y)2;       3) (6a–4b)2;          4) (5z–t)2;

 

368.       1) (3a2+1)2;       2) (a2+1)2;          3) (2x2+3n2)2;       4) (x2+y2)2.

 

369.       1) (m–)2;         2) (a–)2;           3) ;           4) .

 

370.       1) (0,2x+0,3y)2;         3) ;

          2) (0,4b–0,5c)2;         4) .

 

371.       1) ;          3) (–8p3+5p2)2;

          2) ;                           4) (10x2–3xy3)2.

 

372.  1) (–4ab–5a2)2 ;           3) (0,2x2+5xy)2;

          2) (–3b2–2ab)2 ;            4) (4xy+0,5y2)2 .

 

Qisqa ko‘paytirish formulalaridan foydalanib, amallarni bajaring (373–375):

 

373.       1) (90–1)2;       2) (40+1)2;            3) 1012;                 4) 982;

 

374.       1) 9992;           2) 10032;               3) 512;                  4) 392.

 

375.       1) 722;             2) 572;                  3) 9972;                 4) 10012.

 

Ifodani soddalashtiring (376–377):

 

376.       1) (x–y)2+(x+y)2;                 3) (2a+b)2–(2a–b)2;

          2) (x+y)2–(x–y)2;                 4) (2a+b)2+(2a–b)2.

 

377.       1) (3a–1)2+2(1+a)2;   3) (x–1)2–4(x+1)2;

           2) 3(2–a)2+4(a–5)2;           4) –(3+x)2+5(1–x)2.

 

Tenglamani yeching (378–379):

 

378.       1) 16x2–(4x–5)2=15;  3) –5x(x–3)+5(x–1)2= –20;

          2) 64x2–(3–8x)2=87;           4) (2x–3)2–(2x+3)2=12.

 

379.       1) (3x–1)2–(3x–2)2=0;         3) (x+3)(x+7)–(x+4)2=0;

           2) (y–2)(y+3)–(y–2)2=5;     4) (y+8)2–(y+9)(y–5)=117.

 

380.       Ifodaning qiymatini toping:

1) 9a3–a(3a+2)2+4a(3a+7),  bunda  a= –1;

2) (2y–5)2–4(y–3)2–4y,  bunda  y= –;

3) 42m(m–1)–(5m–3)2–6m,  bunda  m= –0,3;

4) 24x2–(7x–2)2+(5x–3)(5x+1), bunda x= –.

 

381.       x ni birhad bilan shunday almashtiringki, natijada tenglik bajarilsin:

1) (x–4b7)2=25a4b2–40a2b8+16b14;

2) (x+7c)2=25b2+70b3c+49c2;

3) (10m5+x)2=100m10+120m7n3+36m4n6;

4) (5b2–x)2=25b4–30a2b3+9a4b2.

 

382.       Ifodani ikkihadning kvadrati shaklida ifodalang:

1) a2–10ab+25b2;               2) k4+2k2+1;

3) 25+10x+x2;                     4) p2–1,6p+0,64.

 

x ni birhad bilan shunday almashtiringki, natijada ikkihadning kvadrati hosil bo’lsin (383–385):

 

383.       1) a2+4a+x;              3) 36a2–x+49b2;

          2) p2–0,5p+x;           4) a2–6ab+x.

 

384.       1) m4–3m2+x;            3) 4a2–5a+x;

          2) a2+ab+x;             4) x+6a+9a2.

 

385.       Isbot qiling:

1) (a–b)2=(b–a)2;                4) (a–b)3=–(b–a)3;

2) (–a–b)2=(b+a)2;             5) (a+b)3=a3+3a2b+3ab2+b3;

3) (–a–b)(a+b)= –(a+b)2;  6) (a–b)3=a3–3a2b+3ab2–b3.