M a sh q l a r

55. Algebraik yig‘indini qavslarsiz yozing:

1) (4)+(–3)–(+7); 3) (–a)+(–7b)+c;

2) (–4)+(–9)–(–11); 4) 2a+(–3b)–4c.

56. Algebraik yig‘indining qo‘shiluvchilarini ayting:

1) 15–c; 2) m–7; 3) –a+47; 4) –13–b.

57. Algebraik yig‘indini yig‘indi shaklida yozing:

1) a–b+c; 2) a–2–b; 3) 2+b–c; 4) 3+a–b–c.

Qavslarni oching (58–59):

58. 1) a+(2b–3c); 2) a–(2b–3c); 3) a–(2b+3c); 4) –(a–2b+3c).

59. 1) a+(b–(c–d)); 2) a–(b–(c–d); 3) a–((b–c)–d); 4) a–(b+(c–(d–k))).

60. Qavslarni oching va soddalashtiring:

1) 3a–(a+2b); 3) 4a+(2a–(3a+2);

2) 5x–(2y–3x); 4) 3m–(5m–(2m–1));

61. m yoki (–m) sonlaridan boshlab, barcha qo‘shiluvchilarni qavs oldiga “+” ishorasini qo‘ygan holda qavs ichiga oling:

1) a+2b+m–c; 3) a–m+3c+4d;

2) a–2b+m+c; 4) a–m+3b²–2a³.

62. m yoki (–m) sonlaridan boshlab, barcha qo‘shiluvchilarni qavs oldiga “–” ishorasini qo‘ygan holda qavs ichiga oling:

1) 2a+3b+m–c; 3) c–m–2a+3b²;

2) 2a+b+m+3c; 4) a–m+3b²–2a³.

63. 1) a+b–1 ifodani biri a ga teng bo‘lgan ikkita qo‘shiluvchilarning yig‘indisi shaklida yozning;

2) a–b+1 ifodani kamayuvchisi a bo‘lgan ayirma shaklida yozning;

3) 2a–b+4 ifodani kamayuvchisi 2a bo‘lgan ayirma shaklida yozning;

4) a–2b+8 ifodani biri 8 ga teng bo‘lgan ikkita qo‘shiluvchilarning yig‘indisi shaklida yozning;

64. Tengliklarning chap qismlari bir xil. Nega o‘ng qismlari har xil? Qanday shartlarda tenglik o‘rinli bo‘ladi?

1) 2400 + 750 : 15 – 40 · 3 = 2330;

2) 2400 + 750 : 15 – 40 · 3 = 90;

3) 2400 + 750 : 15 – 40 · 3 = 2430;

4) 2400 + 750 : 15 – 40 · 3 = 2310;

5) 2400 + 750 : 15 – 40 · 3 = 7210;

6) 2400 + 750 : 15 – 40 · 3 = 2407;

7) 2400 + 750 : 15 – 40 · 3 = 510.

65. Ko‘p nuqtalar o‘rniga “+” va “–” ishoralarini shunday qo‘yingki, natijada to‘g‘ri tenglik hosil bo‘lsin:

1) a–(b+c)=a+(…b …c); 3) m–(n–a)=m+(…n …a);

2) c+(a–b)=c+(…a …b); 4) n–(d–l)=n+(…d …l).

66. Soddalashtiring:

1) (5a–2b)–(3b–5a); 3) 7x+3y–(–3x+3y);

2) (6a–b)–(2a+3b); 4) 8x(3x–2y)–5y.

67. Tenglamani yeching:

1) (2x+1)+3x=16; 3) (x–5)–(5–3x)=2;

2) (x–4)+(x+6)=4; 4) 23–(x+5)=13.

68. Ifodani avval soddalashtirib, keyin uning son qiymatini toping:

1) (2c+5d)–(c+4d), bunda c=0,4, d=0,6;

2) (3a–4b)–(2a–3b), bunda a=0,12, b=1,28;

3) (7x+8y)–(5x–2y), bunda x=, y=0,025;

4) (5c–6b)–(3c–5b), bunda c=–0,25, b=.